A current of I amperes flows through a resistance of R ohms according to the probability distribution
fI(i)= 2i, 0 ≤ i ≤ 1
Suppose that the resistance is also a random variable with probability distribution
FR(r)= 1, 0 ≤ r ≤ 1
Assume that I and R are independent.
(a) Find the probability distribution for the power (in watts) P = I2R.
(b) Find E(P).
No comments:
Post a Comment