Friday, October 10, 2014

A potential difference V is applied to a wire of cross-sectional area A, length L, and resistivity...

A potential difference V is applied to a wire of cross-sectional area A, length L, and resistivity  ρ. You want to change the applied potential difference and stretch the wire so that the energy dissipation rate is multiplied by 30.0 and the current is multiplied by 4.00. Assuming the wire\"s density does not charge, what are (a) the ratio of the new length to L and (b) the ratio of the new cross-sectional area to A?

No comments:

Post a Comment