A thin diverging glass (index = 1.50) lens with R 1 = -3.00 m and R 2 = -6.00 m is surrounded by...

A thin diverging glass (index = 1.50) lens with R₁ = -3.00 m and R₂= -6.00 m is surrounded by air. An arrow is placed 10.0 m to the left of the lens.

(a) Determine the position of the image. Repeat part (a) with the arrow and lens immersed in (b) water (index = 1.33); (c) a medium with an index of refraction of 2.00.

(d) How can a lens that is diverging in air be changed into a converging lens.